Question

(2x^2+45x-47=0)pls solve this question with proper explanation for the right answer I will mark u as brainliest​

Answer 1

Answer:

1

Step-by-step explanation:

By factorising , we have,

2x^2 + (47 - 2)x - 47 = 0

[constant term = 2×(-47) = -94]

So , we had splited the mid term (45x) into

(47 - 2)x .

Now,

2x^2 + 47x - 2x -47 = 0

x(2x + 47) - 1(2x + 47) = 0

(x - 1)(2x + 47) = 0

(x - 1) = 0 / (2x + 47)

Or, x - 1 = 0

x = 1

Hence , 1 is the required answer.

Answer 2

2x² +45x -47 = 0

➾2x²+(47-2)x - 47=0

➾x(2x-47) -1(2x-47)=0

➾(x-1)•(2x-47)=0

➾x-1=0 / ➾2x=47

➾x=1 / ➾ x= ⁴⁷/₂

∴ x=1 ℴℛ ⁴⁷/₂

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