Question

2x^2 + 4a - 6 (factorise)​

Answer 1

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$\it\huge\mathfrak\red{Hello}$]

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=2x×2+4a-6

=2(${x}^{2}$+2a-3)

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$\it\huge\mathfrak\red{thanks}$]

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Answer 2

If it is =>

2x^2 + 4a - 6 (factorise)

ANSWER

2(x^2 + 2a - 3)

If it is =>

2x^2 + 4x - 6 (factorise)

ANSWER

2x^2 + 4x - 6

It is an quadratic polynomial and can be factorised in 3 different methods and we shall use the

1)Middle term Split method to solve this.

So we get =>

2x^2 + 4x - 6

=>2x^2 +6x -2x - 6

=> 2x(x+3) -2(x + 3)

=>(x+3)(2x-2)

So,

either x = -3

or x = 1

Hence we get (x-1) and (x+3 ) as the factors of polynomial.

2)Quadratic Formula method

here,

D = b^2 - 4ac

=>D = 16 +(4)(2)(6)

=>D = 16 + 48

=>D = 64.

Now,

x = $\dfrac{-b\pm\sqrt d}{2a}$

=>x=$\dfrac{-6\pm\sqrt64}{2\times 2}$

=>x=$\dfrac{-6\pm 8}{4}$

So,

either x = -3

or x = 1

Extra information

The 3 methods to solve quadratic equations are =>

1)Middle term Split method

2)Quadratic Formula method and

3)Completing Square Methord.