Question

2x^2-4x-1=0 completing the square

Answer 1

Answer:

Equation: 2x² - 4x - 1 = 0

Dividing by the coefficient of 'x²' we get,

=> x² - 2x - 1/2 = 0

Adding the half of  coefficient of x we get,

Half of coefficient of x = 2 / 2 = 1

Hence we get,

=> x² - 2x + 1 - 1/2 = 1

Transposing -1/2 to the RHS we get,

=> x² - 2x + 1 = 1 + 1/2

=> ( x - 1 )² = 3/2

Taking Square root on both sides we get,

=> x - 1 = ± √ ( 3/2 )

=> x = 1 ± √ ( 3/2 )

This is the required answer !