Question

2x^2+4x-198=0 solve by factorization method.
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Answer 1

Answer:

Hey mate! Here's your answer:

Step-by-step explanation:

2x² + 4x - 198 = 0

x² + 2x - 99 = 0

Now, we have to get 2 numbers whose sum is 2 and product is -99.

Those two numbers are 11 and -9.

x² - 9x + 11x - 99 = 0

x(x - 9) + 11(x - 9) = 0

(x + 11)(x - 9) = 0.

Now,

x + 11 = 0

x = -11.

x - 9 = 0

x = 9.

So the two solutions to this Quadratic Equation are x = -11 and x = 9.

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