Math, asked by kusumpakira727, 10 months ago

2x^2+4x+3= 0 by factoisation

Answers

Answered by ishanit
9
Hello friend,
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Here is the best answer

2 {x}^{2}  + 4x + 3 = 0
d =  {b}^{2}  - 4ac
  = {4}^{2}  - 4(2)(3)
 = 16 - 24
 =  - 8

 = \: d  \: \: is \:  \: negetive
roots are not real
x =  \frac{ - b \binom{ + }{ - } \sqrt{d}  }{2a}
x =  \frac{ - 4 \binom{ + }{ - }  \sqrt{ - 8} }{2}
x =  - 2 \binom{ + }{ - }  \sqrt{2}  \sqrt{ - 1}
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ishanit: please mark as brainlist
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