Question

2x^2-4x-3=0 find alpha^2+beta^2​

Answer 1

Answer:

$\alpha ^{2} + \beta^{2} \\ = ( \alpha + \beta )^{2} - 2 \alpha \beta \\ =( 4 \div 2)^{2} - 2 \times - 3 \div 2 \\ = 4 + 3 \\ = 7$