Math, asked by ojasvisood343, 7 months ago

2x^2-4x+3=0 find roots of quadratic equation by complete square method

Answers

Answered by pavan2005rajak
0

Step-by-step explanation:

The nature of quadratic equation is no real roots.

Step-by-step explanation:

Given : Quadratic equation 2x^2-4x+3=02x

2

−4x+3=0

To find : Nature of the roots of quadratic equation?

Solution :

To determine the nature we find discriminant, D=b^2-4acD=b

2

−4ac

1) If D<0, no real roots.

2) If D=0, two equal real roots.

3) If D>0, two distinct real roots.

Now, we find discriminant.

2x^2-4x+3=02x

2

−4x+3=0

Here, a=2,b=-4,c=3

D=(-4)^2-4(2)(3)D=(−4)

2

−4(2)(3)

D=16-24D=16−24

D=-8D=−8

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