2x^2-4x+3=0 find roots of quadratic equation by complete square method
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Step-by-step explanation:
The nature of quadratic equation is no real roots.
Step-by-step explanation:
Given : Quadratic equation 2x^2-4x+3=02x
2
−4x+3=0
To find : Nature of the roots of quadratic equation?
Solution :
To determine the nature we find discriminant, D=b^2-4acD=b
2
−4ac
1) If D<0, no real roots.
2) If D=0, two equal real roots.
3) If D>0, two distinct real roots.
Now, we find discriminant.
2x^2-4x+3=02x
2
−4x+3=0
Here, a=2,b=-4,c=3
D=(-4)^2-4(2)(3)D=(−4)
2
−4(2)(3)
D=16-24D=16−24
D=-8D=−8
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