Question

2x^2_4x+3=0
solve this plz​

Answer 1

Answer: Here discriminant d=-8

Since, d<0 has no real roots

Step-by-step explanation:

Given,

2x^2_4x+3=0

We have to see the solution using the formula,

x=$-b+-\frac{\sqrt{b^{2-4*a*c} } }{2*a}$

x =  −+b − √(b2 − 4ac)/2a

Here a=2

b=4

c=3

-(-4 )− +√(-4)^2 − 4*2*3)/2*2

4− +√16 − 24)/4

4− +√-8/4

Here, Here discriminant d=-8

Since, d<0 has no real roots

Answer 2

Answer:

Here discriminant d=-8

Since, d<0 has no real roots

Step-by-step explanation:

Given,

2x^2_4x+3=0

We have to see the solution using the formula,

x=-b+-\frac{\sqrt{b^{2-4*a*c} } }{2*a}−b+−

2∗a

b

2−4∗a∗c

x = −+b − √(b2 − 4ac)/2a

Here a=2

b=4

c=3

-(-4 )− +√(-4)^2 − 4*2*3)/2*2

4− +√16 − 24)/4

4− +√-8/4

Here, Here discriminant d=-8

Since, d<0 has no real roots

Step-by-step explanation:

hi mehek did you remember me