Question

2x^2+4x-8=0 find root by completing square method

Answer 1

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Topic:- Completing Square method


2x²+4x-8=0


Multiply 2 in Equation :-


2(2x²+4x-8)=0×2

4x²+8x-16=0

(2x)²+2.2x.2 -(2)²+(2)²-16=0

(2x-2)²+4-16=0

(2x-2)²-12=0

(2x-2)²=12

2x-2=√12

2x-2=2√3



2x=2√3+2

x=2√3+2/2


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2x-2=-2√3

2x=-2√3+2

x=-2√3+2/2


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