Question

2x^2-4x+m=0 is 1 then m value is
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Answer 1

Answer:

-6{67}

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

The value of m so that the equation x^2-4x+(m-4)=0x

2

−4x+(m−4)=0 has equal roots is 8

Step-by-step explanation:

The given quadratic equation is

x^2-4x+(m-4)=0x

2

−4x+(m−4)=0

We know that discriminant of a quadratic equation ax^2+bx+c=0ax

2

+bx+c=0 is given by

D=b^2-4acD=b

2

−4ac