Question

2x^2 – 5 = 0
plz explain and answer...
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Answer 1

Step-by-step explanation:

$2x^2 – 5 = 0 \\ {x}^{2} = \frac{5}{2} \\ x = \sqrt{ \frac{5}{2} } \\ x = \sqrt{ \frac{5}{2} } , - \sqrt{ \frac{5}{2} }$

Answer 2

$\huge\star\pink{solution}$

$= 2x {}^{2} - 5 = 0 \\ \\ divede \: 2 \: this \: equition \\ \\ = > \frac{2x {}^{2} }{2} - \frac{5}{2} = \frac{0}{2} \\ \\ x {}^{2} - \frac{5}{2} = 0 \\ \\ = > x {}^{2} - (\sqrt{ \frac{5}{2} } ) {}^{2} = 0 \\ \\ (x + \sqrt{ \frac{5}{2} } )(x - \sqrt{ \frac{5}{2} }) = 0 \\ \\ to \\ x = - \sqrt{ \frac{5}{2} } , + \sqrt{ \frac{5}{2} }$

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uses formula

$= > x {}^{2} - y {}^{2} =(x + y)(x - y )$

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I hope it helps you