Math, asked by AJchamp, 1 year ago

2x^2+5/2x-2=0 find the zeros

Answers

Answered by azizalasha
0

Answer:

(5±√89)/8

Step-by-step explanation:

2x^2+5/2x-2=0

2x² + 5/2x - 2 = 0

x² + 5/4x - 1 = 0

x = 5/4 ±√89/4 ÷ 2

x = (5±√89)/8

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