2x^2+5/2x-2=0 find the zeros
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Answer:
(5±√89)/8
Step-by-step explanation:
2x^2+5/2x-2=0
2x² + 5/2x - 2 = 0
x² + 5/4x - 1 = 0
x = 5/4 ±√89/4 ÷ 2
x = (5±√89)/8
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