Question

2x^2+√5-5=0 solve using quadratic formula

Answer 1

Standard Quadratic Equation:

ax2+bx+c=0

Where,

a is the constant with x to the power 2.

b is the constant with x to the power 1.

c is the constant.

Standard Quadratic Formula:

x=−b±√b2−4(a)(c)2(a)

Given Equation:

2x2+5x+5=0

Here,

a = 2

b = 5

c = 5

x=−5±√(5)2−4(2)(5)2(2)

x=−5±√25−404

x=−5±√−154

x=−5±3.87i4

x=−5+3.87i4,x=−5−3.87i4

HOPE THIS WILL HELP YOU MARK AS BRAINLIEST..

Answer 2

use quadratic equation and substitute the valeus

u will get the answer in root

$[-\sqrt{5}+-3\sqrt{5}]/4$