Math, asked by umashankarsharm73341, 4 days ago

2x^2+5-528=0
find the roots of the following quadratic equation

Answers

Answered by ranjithkumarsajeetha
0

Answer:

2x^2+5x -528=0

Here a=0, b= 0, c=0

formula x =

x = −b ± √(b2 − 4ac) / 2a

= -5 ±√ ( 25+4224) / 4

= -5 ±√ 4249 / 4

= -5±65.18/ 4

x= -5+65.18/4 ; x= -5-65.18/4

x= 60.18/4 ; x= -70.18/4

x= 15.045 ; X= -17.545

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