2x^2+5-528=0
find the roots of the following quadratic equation
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Answer:
2x^2+5x -528=0
Here a=0, b= 0, c=0
formula x =
x = −b ± √(b2 − 4ac) / 2a
= -5 ±√ ( 25+4224) / 4
= -5 ±√ 4249 / 4
= -5±65.18/ 4
x= -5+65.18/4 ; x= -5-65.18/4
x= 60.18/4 ; x= -70.18/4
x= 15.045 ; X= -17.545
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