Question

2x^2-5/6x+1/12 :factorise

Answer 1

Solution:

Given Quadratic expression :

2x²-5x/6+1/12

Find L.C.M of 6 and 12 , we get

LCM = 12

= (24x²-10x+1)/12

Splitting the middle term, we get

= (1/12)[24x²-6x-4x+1]

=(1/12)[6x(4x-1)-1(4x-1)]

= (1/12)[(4x-1)(6x-1)]

Therefore,

2x²-5x/6+1/12 = (1/12)(4x-1)(6x-1)

••••

Answer 2

Answer:

The required factors of the equation are : (6x - 1) and (4x - 1)

Step-by-step explanation:

The equation which is to be factorized is given to be :

2x² - 5/6x + 1/12 = 0

First multiplying each term of the equation by 12

⇒ 24x² - 10x + 1 = 0

Now, factorize the above equation formed.

⇒ 24x² - 6x - 4x + 1 = 0

⇒ 6x(4x - 1) - 1(4x + 1) = 0

⇒ (6x - 1)·(4x - 1) = 0

⇒ x = 1/6 or x = 1/4

Thus, The required factors of the equation are : (6x - 1) and (4x - 1)