Question

2x^2 - 5 y^2 * x^2 + 3y^2 find the product​

Answer 1

Step-by-step explanation:

(2x+5y)(2x+3y)

Using,

(x+a)(x+b)=x

2

+(a+b)x+ab

Comparing we get,

x=2x,a=5y,b=3y

=(2x+5y)(2x+3y)

=(2x)

2

+(5y+3y)2x+(5y)×(3y)

=4x

2

+16xy

2

+15y

2

Answer 2

Answer:

answer is "0"

2x2-5y2*x2+3y

2x4+6x2y2-5x2y2-15y4

2x2(x2+3y2) -5y2(x2+3y2)

2x2-5y2 and x2+3y

2x2 = 5y2 and x2= - 3y2

it put in equation

5y2-5y2*-3y2+3y2

- 15y4 + 15y4 +15y4 -15y4

0+0 =0

the answer is 0