Math, asked by abhisharma744701385, 11 months ago

2x^2+5x-3 find the zeroes of the polynomial and verify the relationship between their zeroes and coefficient​

Answers

Answered by vaishnavitiwari1041
9

Answer:

✅Here's your answer

2 {x}^{2}  + 5x - 3 \\  \\ 2 {x}^{2}   - x + 6x - 3 \\  \\ x(2 x - 1) + 3(2x - 1) \\  \\ (2x - 1)(x + 3) \\  \\  \alpha  =  \frac{1}{2}  \:  \: and \:  \:  \beta  =  - 3 \\  \\

 \alpha  +  \beta  =  \frac{ - b}{a}  \\  \\  \frac{1}{2}  + ( - 3) =   \frac{ - 5}{2}  \\  \\  \frac{ - 5}{2}  =  - \frac{ - 5}{2}  \\  \\  \  \alpha  \beta  =  \frac{c}{a}  \\  \\

 \frac{ - 3}{2}  =  \frac{ - 3}{2}

Hence verified!!

Hope it helps ...

Answered by Sahil1231
0

Step-by-step explanation:

2x^2+5x-3=0

2x^2+6x-x-3=0

2x(x+3)-1(x+3)=0

(2x-1)(x+3)

x=1/2 or x= -3

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