2x^2+5xy+3y^2+ay-10=(2x+3y+b)(x+y-2) then what will be the value of a and b
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put x=0,y=1
0+0+3+a-10=(3+b)(-1)....................(1)
put y=0,x=0
0+0+0+0-10=b(-2)
b=5......(2)
solve (1) by (2)
0+0+3+a-10=(3+b)(-1)....................(1)
put y=0,x=0
0+0+0+0-10=b(-2)
b=5......(2)
solve (1) by (2)
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