Question

2x^2-6x+1=0 find the value of x

Answer 1

Hi,

Here is your answer

2x² - 6x + 1 = 0

x = - b ± √(b² - 4ac) / 2a

x = - (- 6) ± √[(-6)² - 4*2*1] / 2*2

x = 6 ± √(36 - 8) / 4

x = 6 ± √28 / 4

x = 6 ± 5.29 / 4

x = 6+5.29 /4 or 6 - 5.29/4

x = 2.82 or 0.1775

The value of x may be 2.82 or 0.1775

I hope I have cleared your doubt.

Answer 2

↑ Here is your answer ↓
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Given polynomial,

$2x^2 - 6x + 1 = 0$

Lets solve,

$= b^2 - 4 ac$

$= (-6)^2 - 4(2)(1)$

$= 36 - 8$

$= 28$

Use quadratic formula now,

$= (-b \pm \sqrt {b^2 - 4ac})/ 2a$

$= (6 \pm \sqrt{28})/4$

$= (6 \pm 2 \sqrt 7)/4$

$= 3/2 \pm \sqrt 7 /2$