Question

2x^2-6x+3=0 by nature root method​

Answer 1

Answer:

Solution : The given equation is 2x2-6x+3=0. This is of the form ax2+bx+c=0, where a=2, b=-6 and c=3. ∴ D=(b2-4ac)={(-6)2-4×2×3}=(36-24)=12>0

Step-by-step explanation:

Hope its helps you very much

Answer 2

2x²-6x+3=0

compare equation with ax²+bx+c=0

a=2,b=-6,c=3

b²-4ac=(-6)-4×2×3

=36-24

= 12

b²-4ac<0

therefore the roots of quadratic equation is real and unequal.