Question

2x^2+6x=32
find the value of x

Answer 1

Step-by-step explanation:

2x=32-6+2 2x=16+2 2x=18

x=18/2

x=9

Answer 2

Answer:

$x = \dfrac{-3 + \sqrt{73}}{2} \: or \: x = \dfrac{-3 - \sqrt{73}}{2}$

Step-by-step explanation:

$2x^2 + 6x = 32\\\\\\\implies 2x^2 + 6 - 32 = 0\\\\\\\implies 2(x^2 + 3x - 16) = 0\\\\\\\implies x^2 + 3x - 16 = 0 \div 2 = 0\\\\\\\text{Here, a = 1; b = 3; c = -16}\\\\\\\text{Using quadratic formula,}\\\\\\x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\\\= \dfrac{-3 \pm \sqrt{9 - 4(1)(-16)}}{2}\\\\\\= \dfrac{-3 \pm \sqrt{9 + 64}}{2}\\\\\\\therefore x = \dfrac{-3 + \sqrt{73}}{2} \: or \: x = \dfrac{-3 - \sqrt{73}}{2}$