Math, asked by ritaachhetri428, 18 days ago

(2x^2-7)^5 6(2x-3)^5×2-(2x-3)^6 5(2x^2-7)^4×4x÷(2x^2-7)^10 how to solve this problem

Answers

Answered by kaviyasri28610
0

Answer:

(2x^2-7)^5 6(2x-3)^5x2-(2x-3)^6

5(2x^2-7)^4x4x÷(2x^2-7)^10

Step-by-step explanation:

(5b⁶x²-(2x-1)²-6) (2x-3)^, 20x-3)^,20xx4(2x²-7)¹

( 4x-7)¹⁰

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