2x^2-7x=0. Solve by factorization method only otherwise I will report the ans . and pls help me
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Answer:x=0;x=7/2
Step-by-step explanation:
2x^2-7x=0 (given)
Taking x as common
x(2x-7)=0
=>Either x=0
or 2x-7=0 <=> x=7/2
Hence there are two values of x.
One is 0 and the other is 7/2.
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