Question

2x^2 -7x+3=0
Find roots by quadratic formula only..

Answer 1

Here is your answer mate

Find the value of D first by formula b^2- 4ac

Then

Find X by the formula X=-b+-√D/2a

You will get the value

3 and 1/2

So it's the answer

Answer 2

Answer:

$2 {x}^{2} - 7x + 3 = 0 \\ = 2 {x}^{2} - 6x - x + 3 = 0 \\ = 2x(x - 3) - 1(x - 3) = 0 \\ = (2x - 1)(x - 3) = 0 \\ = 2x - 1 = 0 \: or \: x - 3 = 0 \\ = x = \frac{1}{2} \: or \: 3$