Question

2x^2+7x+3=0 please find fast​

Answer 1

2$x^{2}$+7x+3=0

2$x^{2}$ +6x + x + 3 =0

2x(x +3) +1(x+3) =0

(2x+1)(x+3) = 0

2x +1 =0

x =  $\frac{-1}{2}$

x+3 =0

x = -3

The values of x are $\frac{-1}{2}$ and -3

Mark as brainliest if it helped :D

Answer 2

ANSWER-

• Simplifying

2x2 + 7x + 3x = 0

• Reorder the terms:

7x + 3x + 2x2 = 0

• Combine like terms: 7x + 3x = 10x

10x + 2x2 = 0

• Solving

10x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.

2x(5 + x) = 0

Ignore the factor 2.

Ignore the factor

Ignore the factor 2.Subproblem 1Set the factor 'x' equal to zero and attempt to solve

• Simplifying

x = 0

• Solving

x = 0

Move all terms containing x to the left, all other terms to the right.

• Simplifying

x = 0

Subproblem 2

Set the factor '(5 + x)' equal to zero and attempt to solve:

• Simplifying

5 + x = 0

• Solving

5 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.

5 + -5 + x = 0 + -5

• Combine like terms: 5 + -5 = 0

0 + x = 0 + -5

x = 0 + -5

• Combine like terms: 0 + -5 = -5

x = -5

• Simplifying

x = -5

❥ Solution

x = {0, -5}

OR

2x^{2}x

2x^{2}x 2

2x^{2}x 2 +7x+3=0

2x^{2}x 2 +7x+3=02x^{2}x

2x^{2}x 2 +7x+3=02x^{2}x 2

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =0

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 0

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2}

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1 x+3 =0

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1 x+3 =0x = -3

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1 x+3 =0x = -3The values of x are \frac{-1}{2}

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1 x+3 =0x = -3The values of x are \frac{-1}{2} 2

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1 x+3 =0x = -3The values of x are \frac{-1}{2} 2−1

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1 x+3 =0x = -3The values of x are \frac{-1}{2} 2−1

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1 x+3 =0x = -3The values of x are \frac{-1}{2} 2−1 and -3

2x^{2}x 2 +7x+3=02x^{2}x 2 +6x + x + 3 =02x(x +3) +1(x+3) =0(2x+1)(x+3) = 02x +1 =0x = \frac{-1}{2} 2−1 x+3 =0x = -3The values of x are \frac{-1}{2} 2−1 and -3Mark as brainliest if it helped :D