Question

2x^2-7x+3=0
Plz answer it fast ☺

Answer 1

Answer:

the answer is 7+5/4 and 7-5/4 is the roots

or 3 and 1/2 re the roots

Answer 2

Step-by-step explanation:

$\implies \sf 2x^2-7x+3=0 \\ \implies \sf 2x^{2} - (1 + 6)x + 3 = 0 \\ \implies \sf 2x^{2} -x - 6x + 3 = 0 \\ \implies \sf x(2x - 1) - 3(2x - 1) = 0 \\ \implies \sf (2x - 1)(x - 3) = 0 \\ \\ \implies \sf 2x - 1 = 0 \\ \implies \sf 2x = 1 \\ \implies \sf x = \frac{1}{2} \\ \\ \implies \sf x - 3 = 0 \\ \implies \sf x = 3 \\ \\ \therefore \sf \: x = \frac{1}{2} \: or \: 3$

Hope it Helps !!!!