2x^2 - 7x +3 = 0 Solve by only completing the square method
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Answers
Answered by
3
2x²-6x-x+3=0
2x(x-3)-1(x-3)=0
(2x-1)(x-3)=0
x=1/2,x=3
2x(x-3)-1(x-3)=0
(2x-1)(x-3)=0
x=1/2,x=3
oh its OK
Answered by
4
Hey!!!...Here is ur answer
2x^2-7x+3=0
2x^2-6x-x+3=0
2x (x-3)-1 (x-3)=0
(x-3)(2x-1)=0
x=3 & x=1/2
Hope it will help you
2x^2-7x+3=0
2x^2-6x-x+3=0
2x (x-3)-1 (x-3)=0
(x-3)(2x-1)=0
x=3 & x=1/2
Hope it will help you
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