Question

2x^2-7x+3=0
solve this by using quadratic formula​

Answer 1

2x²-7x+3=0

+6

-6/-1

2x²-6x-x+3=0

2x²-6x-x+3=02x(x-3)-1(x-3)=0

2x²-6x-x+3=02x(x-3)-1(x-3)=0(2x-1)(x-3)=0

2x-1=0

x=1/2

x-3=0

x=3

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Answer 2

Answer:

x = 3, 1 / 2

Step-by-step explanation:

2x^2 - 7x + 3 = 0

Here,

a = 2

b = - 7

c = 3

D = b^2 - 4ac

= ( - 7 )^2 - 4 ( 2 ) ( 3 )

= 49 - 24

D = 5

x = ( - b ± √D ) / 2a

= ( - ( - 7 ) ± √25 ) / 2 ( 2 )

= ( 7 ± 5 ) / 4

= ( 7 + 5 ) / 4, ( 7 - 5 ) / 4

= 12 / 4, 2 / 4

x = 3, 1 / 2