2x^2+7x+3 by using factor theorem
Answers
Answered by
10
Hey mate ....☺
Here's ur ans. ----
2x^2 + 7x + 3
2x^2 + x + 6x + 3 =0
x( 2x+1) +3(2x+1) = 0
(x+3 ) ( 2x+ 1) =0
x = -3 , -1/2
✌
Here's ur ans. ----
2x^2 + 7x + 3
2x^2 + x + 6x + 3 =0
x( 2x+1) +3(2x+1) = 0
(x+3 ) ( 2x+ 1) =0
x = -3 , -1/2
✌
Answered by
6
so we have a quadratic equation
2x²+7x+3
2x²+6x+1x+3
2x(x+3)+1(x+3)
(2x+1)(x+3)
so 2x²+7x+3 zeroes are
x=-1/2andx=-3
I hope that works
2x²+7x+3
2x²+6x+1x+3
2x(x+3)+1(x+3)
(2x+1)(x+3)
so 2x²+7x+3 zeroes are
x=-1/2andx=-3
I hope that works
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