Question

2x^2-7x+3 find roots​

Answer 1

Step-by-step explanation:

2x^2 - 7x + 3 = 0

2x^2 - 6x - x + 3 = 0

2x(x-3)-1(x-3) = 0

(2x-1)(x-3) = 0

x = 1/2

x = 3

Answer 2

HeYa❤️...

Answer:

$2x {}^{2} - 7 + 3 = 0 \\ 2x {}^{2} + 6x + 1x + 3 = 0 \\ 2x(x + 3) + 1(x + 3) \\ (x + 3)(2x + 1) = 0 \\ \\ \\ hence. \: roots \: of \: equation = > \\ x = - 3 \: and \: x = \frac{ - 1}{2}$

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