√2x^2+7x+5√2
solve it by completing the square method pls it's urgent
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Hey Mate ✌
⏩ Here's your answer,
√2x² + 7x + 5√2
==> Dividing whole equation by √2 ( Co efficient of x2 )
we get,
==> x² + 7x/√2 + 5
==> x² + 7x/√2 = -5 ..........(1)
==> Now third term : (1/2 X coefficient of x)²
==> [ 1/2 X 7/√2]²
==> [7 / 2√2]²
==> Adding third term to both LHS and RHS in eq ( 1)
we get,
x² + 7x/√2+ [7/2√2]² = -5 + [7/2√2]2
==> [x + 7/2√2]² = -5 + 49/8
..........[by using the identity
a² + 2ab +b² = (a + b) ²]
==> [x + 7/2√2]² = 9 / 8
==> Now taking square root on both the sides we get,
==> √[x + 7/2√2]² = √9/8
==> x + 7/2√2 = 3/2√2
==> x = 3/2√2 - 7/2√2
==> x = -4/2√2
==> x = -2/√2
==> x = -2 / √2 X √2/√2
==> x = -2√2/2
==> x = -√2 is the required answer.
⭐ Hope it helps you : ) ⭐
⏩ Here's your answer,
√2x² + 7x + 5√2
==> Dividing whole equation by √2 ( Co efficient of x2 )
we get,
==> x² + 7x/√2 + 5
==> x² + 7x/√2 = -5 ..........(1)
==> Now third term : (1/2 X coefficient of x)²
==> [ 1/2 X 7/√2]²
==> [7 / 2√2]²
==> Adding third term to both LHS and RHS in eq ( 1)
we get,
x² + 7x/√2+ [7/2√2]² = -5 + [7/2√2]2
==> [x + 7/2√2]² = -5 + 49/8
..........[by using the identity
a² + 2ab +b² = (a + b) ²]
==> [x + 7/2√2]² = 9 / 8
==> Now taking square root on both the sides we get,
==> √[x + 7/2√2]² = √9/8
==> x + 7/2√2 = 3/2√2
==> x = 3/2√2 - 7/2√2
==> x = -4/2√2
==> x = -2/√2
==> x = -2 / √2 X √2/√2
==> x = -2√2/2
==> x = -√2 is the required answer.
⭐ Hope it helps you : ) ⭐
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