Question

√2x^2+7x+5√2

solve it by completing the square method pls it's urgent

Answer 1

Hey Mate ✌

⏩ Here's your answer,

√2x² + 7x + 5√2

==> Dividing whole equation by √2 ( Co efficient of x2 )

we get,

==> x² + 7x/√2 + 5

==> x² + 7x/√2 = -5 ..........(1)

==> Now third term : (1/2 X coefficient of x)²

==> [ 1/2 X 7/√2]²

==> [7 / 2√2]²

==> Adding third term to both LHS and RHS in eq ( 1)

we get,

x² + 7x/√2+ [7/2√2]² = -5 + [7/2√2]2

==> [x + 7/2√2]² = -5 + 49/8
..........[by using the identity
a² + 2ab +b² = (a + b) ²]

==> [x + 7/2√2]² = 9 / 8

==> Now taking square root on both the sides we get,

==> √[x + 7/2√2]² = √9/8

==> x + 7/2√2 = 3/2√2

==> x = 3/2√2 - 7/2√2

==> x = -4/2√2

==> x = -2/√2

==> x = -2 / √2 X √2/√2

==> x = -2√2/2

==> x = -√2 is the required answer.

⭐ Hope it helps you : ) ⭐