Question

2x^2+7x-9 factorise the number

Answer 1

Step-by-step explanation:

$\sf 2{x}^{2} + 7x - 9 \\ \\ \sf 2{x}^{2} - 2x + 9x - 9 \\ \\ \sf 2x ( x - 1 ) + 9 ( x - 1 ) \\ \\ \sf (x-1)(2x+9)$

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Answer 2

SOLUTION :

$\sf 2x^2 + 7x - 9$

$\sf = 2x^2 + ( 9 - 2 ) x - 9$

$\sf = 2x^2 + 9x - 2x - 9$

$\sf = x ( 2x + 9 ) - 1 ( 2x + 9 )$

$\sf = ( x - 1 ) ( 2x + 9 )$

Now,

• x - 1 = 0 ; x = 1
• 2x + 9 = 0 ; 2x = -9 ; x = -9/2

$\rule{200}2$