2x^2+800x-1920000=0 factorise
Answers
Answered by
2
Answer:
2x²+800x-1920000=2(x-800)(x+1200)
Step-by-step explanation:
2x²+800x-1920000=0
2(x²+400x-960000)=0
x=(-400±√400²+4*1*960000)/2
=(-400±√160000+3840000)/2
=(-400±√4000000)/2
x=(-400±2000)/2
x=(-400+2000)/2=1600/2=800
and x=(-400-2000)/2=-2400/=-1200
x=800,x-800=0
and x=-1200,x+1200=0
Hence
2x²+800x-1920000=2(x-800)(x+1200)
Similar questions
Science,
8 months ago
Social Sciences,
8 months ago
Social Sciences,
8 months ago
Math,
1 year ago
Math,
1 year ago