Question

2x^2+800x-1920000=0 factorise

Answer 1

Answer:

2x²+800x-1920000=2(x-800)(x+1200)

Step-by-step explanation:

2x²+800x-1920000=0

2(x²+400x-960000)=0

x=(-400±√400²+4*1*960000)/2

=(-400±√160000+3840000)/2

=(-400±√4000000)/2

x=(-400±2000)/2

x=(-400+2000)/2=1600/2=800

and x=(-400-2000)/2=-2400/=-1200

x=800,x-800=0

and x=-1200,x+1200=0

Hence

2x²+800x-1920000=2(x-800)(x+1200)