Question

2x^2-9x+10=0,when\ x\ \in \ \ n

Answer 1

Answer:

Consider the given equation.

2x2−9x+10=0

Comparing that,

ax2+bx+c=0 we get,

a=2,b=−9,c=10

Then, using quadratic equation formula,

  x=2a−b±b2−4ac

 x=2×29±(−9)2−4×2×10

 x=49±81−80

 x=49±1

Taking +ive,

x=49+1=410=25

Taking –ive,

x=49−1=48=2

Step-by-step explanation:

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