Question

2x^2+ax+root2=1 find the value of a​

Answer 1

Let's solve for a

2x2+ax+root2=1

Step 1: Add -o^2rt^2 to both sides.

o2rt2+ax+2x2+−o2rt2=1+−o2rt2

ax+2x2=−o2rt2+1

Step 2: Add -2x^2 to both sides.

ax+2x2+−2x2=−o2rt2+1+−2x2

ax=−o2rt2−2x2+1

Step 3: Divide both sides by x

axx=−o2rt2−2x2+1x

a=−o2rt2−2x2+1x

$\huge\underbrace\mathbb{Answer}$

a=−o2rt2−2x2+1x