Question

2x^2- (b-4) x -4 ( b+2) =0 has equal roots, find the possible values of b

Answer 1

Answer:

When roots are equal, then

$d = {b}^{2} - 4ac \: = 0$

D = (b-4)2 - 4 x2x(-4(b+2))

0= b2 +16 -8b +32b-16

0= b2 +24b

0= b(b+24)

b=0,b =-24