Question

2x^2-kx+1=0find the value of Q in the following quadratic equation have real and equal root ​

Answer 1

here is your ans.

for real and equal roots

d = 0

b²-4ac = 0

k² - 4(2)(1)= 0

k = +- 2√2

Answer 2

Answer:

k=2√2,k=-2√2

Step-by-step explanation:

for real and equal roots ,

d=b^2-4ac

so,d=0

b^2-4ac=0

here,b=-k,a=2,c=1

(-k)^2-4*2*1=0

k^2-8=0

k^2=8

k=+-√8

or

k=+-2√2

is the answer