Question

2x^2+Kx+√2 if x-1 is a factor of p(x)​

Answer 1

Answer:

if x−1 is a factor of given eq

n

then it

will satisfy this eq

n

,x−1=0,x=1kx,

2x

2

+kx+

2

2+k+

2

=0

k=−(

2

+2)

Step-by-step explanation:

hope it maybe helpful for you

Answer 2

Answer:

$2 {x}^{2} + kx + \sqrt{2} = 0 \: at \: x = 1 \\ 2( {1}^{2} ) + k(1) + \sqrt{2} = 0 \\ 2 + k + \sqrt{2} = 0 \\ k = - 2 - \sqrt{2} = - (2 + \sqrt{2} )$

If x-1 is a factor then k = -(2+√2)