Question

2x^2-root 5x+1=0 has how many 0

Answer 1

Answer:

This quadratic equation has two complex roots but no real zeroes.

Step-by-step explanation:

$a = 2 \\ b = - \sqrt{5} \\ c = 1 \\ now \: discriminant = {b}^{2} - 4ac \\ = ( - { \sqrt{5}) }^{2} - 4 \times 2 \times 1 \\ 5 - 8 \\ = - 3 \\ it \: mean \: equation \: has \: no \: real \: zeroes$