Question

2x^2+x+1=0
find discriminant​

Answer 1

Answer:

2x²+X+1=0

a=2,b=1,c=1

D=b²-4ac

= (1)²-4(2)(1)

=1-8

=-7<0

Roots does not exist.

Answer 2

Heyaa☺

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2x^2 + x + 1 = 0

Here,

a = 2; b = 1; c = 1

Discriminant =》 b^2 - 4ac

=》 (1)^2 - 4(2)(1)

=》 1 - 8

=》 -7.

Discriminant is less than 0. i.e, the roots arw not real.

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Hope you understand...✌