2x^2+x-1/5=0
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Answered by
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Answer:
x = -5 + √ 65 / 20
Step-by-step explanation:
Common factor
2x^2 + x - 1/5 = 0
1/5 ( 10 x^2 + 5x - 1 ) = 0
Divide both sides of the equation by the same term..
1/5 ( 10x^2 + 5x - 1 ) = 0
10x^2 + 5x - 1 = 0
Use the quadratic formula
x = - b + √ b^2 - 4ac / 2a
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
10x^2 + 5x - 1 = 0
a = 10
b = 5
c = -1
x = -5 + √ 5^2 - 4 . 10 ( -1 ) / 2.10
Simplify
- Evaluate the exponent
- Evaluate the exponentMultiply the numbers
- Evaluate the exponentMultiply the numbersAdd the numbers
- Evaluate the exponentMultiply the numbersAdd the numbersMultiply the numbers
x = -5 + √ 65 / 20
Separate the equations
To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.
x = -5 + √ 65 / 20
x = -5 - √ 65 / 20
Solve
Rearrange and isolate the variable to find each solution
x = -5 + √ 65 / 20
x = -5 - √ 65
==>>> x = -5 + √ 65 / 20....
Hope it's help you ✌️✌️
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Step-by-step explanation:
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