Math, asked by samadhanbadgujar897, 16 days ago

2x^2+x-1/5=0

help army its urgent

Answers

Answered by cutegirl1541984
5

Answer:

x = -5 + 65 / 20

Step-by-step explanation:

Common factor

2x^2 + x - 1/5 = 0

1/5 ( 10 x^2 + 5x - 1 ) = 0

Divide both sides of the equation by the same term..

1/5 ( 10x^2 + 5x - 1 ) = 0

10x^2 + 5x - 1 = 0

Use the quadratic formula

x = - b + b^2 - 4ac / 2a

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

10x^2 + 5x - 1 = 0

a = 10

b = 5

c = -1

x = -5 + 5^2 - 4 . 10 ( -1 ) / 2.10

Simplify

  • Evaluate the exponent
  • Evaluate the exponentMultiply the numbers
  • Evaluate the exponentMultiply the numbersAdd the numbers
  • Evaluate the exponentMultiply the numbersAdd the numbersMultiply the numbers

x = -5 + 65 / 20

Separate the equations

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

x = -5 + 65 / 20

x = -5 - 65 / 20

Solve

Rearrange and isolate the variable to find each solution

x = -5 + 65 / 20

x = -5 - 65

==>>> x = -5 + √ 65 / 20....

Hope it's help you ✌️✌️

Answered by appalanaidu8006
6

Step-by-step explanation:

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