Question

2x^2-x+1/8=0

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Answer 1

Step-by-step explanation:

2x^2-x+1/8=0

(16x^2-8x+1)/8=0

16 x ^2-8 x +1 = 0×8 = 0

perfect square of 16 is -4 and -4

so we can write this equation as

16x^2-4x-4x+1=0

4x(4x-1)-1(4x-1) = 0

(4x-1)(4x-1) = 0

4x-1 = 0

so tha answer is

x= 1/4