Math, asked by binikalita588, 7 months ago

2x^2-x+1/8=0 by factorisation?

Answers

Answered by anu012

12

2x^2-x+1/8=0

=16x^2-8x+1=0

=16x^2-4x-4x+1=0

=4x(4x-1)-1(4x-1)=0

=(4x-1)^2=0

=4x=1

=x=1/4

this is ur answer

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