Question

2x^2-x+1/8=0 middle term spilliting​

Answer 1

☆ Answer ☆

(4x-1)(4x-1) = 0

1/4, 1/4 are roots of the equation

explaination

Given quadriatic equation :

${2x}^{2} - x + 1/8 = 0$

Multiply each term by 8

we get,

${16x}^{2} - 8x + 1 = 0$

Splitting the middle term

We get,

${16x}^{2} - 4x - x + 1 = 0$

4x (4x-1)-1 (4x-1) = 0

(4x-1) (4x-1) = 0

4x -1 = 0

4x = 1

x = 1/4

Therefore,

roots of the quadratic equation are 1/4

hope this will help you...

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Answer 2

☆ Answer ☆

(4x-1)(4x-1) = 0

1/4, 1/4 are roots of the equation

explaination

Given quadriatic equation :

{2x}^{2} - x + 1/8 = 02x

2

−x+1/8=0

Multiply each term by 8

we get,

{16x}^{2} - 8x + 1 = 016x

2

−8x+1=0

Splitting the middle term

We get,

{16x}^{2} - 4x - x + 1 = 016x

2

−4x−x+1=0

4x (4x-1)-1 (4x-1) = 0

(4x-1) (4x-1) = 0

4x -1 = 0

4x = 1

x = 1/4

Therefore,

roots of the quadratic equation are 1/4

hope this will help you...

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