Question

2x^2-x+1/8 factorise

Answer 1

Hey...
Here is ur answer in this figure..
Hope this will help u...

Answer 2

Solution:-

$2 {x}^{2} - x + \frac{1}{8} = 0 \\ 16 {x}^{2} - 8x + 1 = 0 \\ 16 {x}^{2} - 4x - 4x + 1 = 0 \\ 4x(x - 1) - 1(4x - 1) = 0 \\ (x -1)(4x - 1) = 0 \\ x = 1 \\ x = \frac{1}{4}$