Math, asked by alimujtaba48667, 3 months ago

2x^2-x-28=0
solve the following question​

Answers

Answered by Anonymous
1

Answer:

» 2x² - x - 28 = 0

» 2x² - 8x + 7x - 28 = 0

» 2x (x - 4) + 7 (x - 4) =

» x = 4 or -7/2

Answered by deepsamanta600
0

Answer:

 {2x}^{2}  - x - 28 = 0 \\  {2x}^{2}  - 8x + 7x  - 28 = 0 \\ 2x(x - 4) + 7(x - 4) = 0 \\ (x - 4)(2x + 7) = 0 \\  \\ (x - 4) = 0 \\ x = 4 \\  \\ (2x + 7) = 0 \\ 2x =  - 7 \\ x =  \frac{ - 7}{2}  \\  \\  \\ x = (4 )\:  \: ..  (\frac{ - 7}{2} ) \:  \:  \: (ans.)

Step-by-step explanation:

please make me brainlist

Similar questions