Math, asked by devbhatt6106, 7 months ago

2x^2-x-3=0 by factorisation ​

Answers

Answered by muskanperween225
0

Answer:

 {2x}^{2}  - x - 3 = 0

 {2x}^{2}  - (3 - 2)x - 3 = 0

 {2x}^{2}  - 3x + 2x - 3 = 0

x(2x - 3) + 1(2x - 3) = 0

(2x - 3)(x + 1) = 0

Answered by SohamAgarwal
0

Answer:

x = -1, 3/2

Step-by-step explanation:

2x^2 - x - 3

= 2x^2 - 3x + 2x - 3

= x ( 2x - 3 ) + 1 ( 2x - 3 )

= (x + 1)(2x - 3) = 0

x = -1, 3/2

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