Question

2x^2+x-3=0 using quadratic equations formula find the root of the following equation​

Answer 1

$2x^{2} + x - 3 = 0$

$2x ^{2} + (3 - 2)x - 3 = 0$

$2x^{2} + 3x - 2x - 3 = 0$

$x(2x + 3) - 1(2x + 3) = 0$

$(2x + 3)(x - 1) = 0$

$either$

$2x + 3 = 0$

$x = \frac{ - 3}{2}$

$or$

$x - 1 = 0$

$x = 1$

Answer 2

Answer:

Step-by-step explanation:

2x2+x-3=2x2+3x-2x-3=x(2x+3)-1(2x+3)

=(x-1)(2x+3)

x=1 or -3/2