Question

2x^2+x-4 =0. By completing rhe square method

Answer 1

Answer:

x= (√33-1)/4

Explanation:

2x²+x-4 = 0

(2x²)/2 + x/2 -4/2 = 0/2 ( dividing both sides by 2)

x² + x/2 -2 = 0

(x)² + 2(x)(1/4) + (1/4)² -(1/4)² -2 = 0 ( Completing the square)

(x + 1/4)² - 1/16 -2 = 0

(x+ 1/4)² = 1/16 +2

(x + 1/4)² = 33/16

x + 1/4 = √(33/16)

x + 1/4 = √33/√16

x + 1/4 = √33/4

x = √33/4 -1/4

x = (√33-1)/4