Question

2x^2+ x -4 =0 quadratic formula copy me likh ke answer bhejo please​

Answer 1

ANSWER:

To Solve:

• 2x^2 + x - 4 = 0

Solution:

We are given that,

$\implies 2x^2+x-4=0$

We know that, by Quadratic Formula,

$\hookrightarrow x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here,

• a = coefficient of x^2 = 2
• b = coefficient of x = 1
• c = constant = -4

So,

$\implies x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\implies x=\dfrac{-1\pm\sqrt{(1)^2-4(2)(-4)}}{2(2)}$

$\implies x=\dfrac{-1\pm\sqrt{1+32}}{4}$

So,

$\implies x=\dfrac{-1\pm\sqrt{33}}{4}$

Hence,

$\implies\bf x=\dfrac{-1+\sqrt{33}}{4}\:\:\&\:\:\dfrac{-1-\sqrt{33}}{4}$

Formula Used:

• $\hookrightarrow \text{Quadratic Formula:}\:\: x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Answer 2

Answer:

the answer is x = (-1 ± √33)/4

Hope it helps!!!

#Be Brainly

Answer 3

Answer:

the answer is x = (-1 ± √33)/4

Hope it helps!!!

#Be Brainly